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siniylev [52]
3 years ago
11

A service station charges $251 for four new tires and installation. If the installation portion of the bill is $84, what is the

price of one tire
Mathematics
1 answer:
ohaa [14]3 years ago
6 0
The answer is $41.75. Subtract $84 from $251 and you get $167. There are 4 tires, so divide by 4 for the price of each individual one, and get $41.75. Hope this helps!! Good luck for your future in school!
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37 degrees Celsius to Fahrenheit ​
konstantin123 [22]
98.6 degrees fahrenheit
5 0
3 years ago
Read 2 more answers
What is the sum of 1 2/5 and 5 3/4​
Art [367]

Answer:

7\frac{3}{20}

Step-by-step explanation:

<em>Hey there!</em>

Well to add this we need to pu it in improper form.

7/5 + 23/4

Now we need to find the LCM.

5 - 5, 10, 15, 20, 25, 30

4 - 4, 8, 12, 16, 20, 24, 28

So the LCD is 20.

Now we need to change the 5 and 4 to 20.

5*4 = 20

7*4 = 28

<u>28/20</u>

4*5=20

23*5=115

<u>115/20</u>

Now we can add 28 and 115,

= 143/20

Simplified

7 3/20

<em>Hope this helps :)</em>

4 0
4 years ago
Read 2 more answers
Find the difference between the polynomials:–3x+x3–2x2 and 4x3–2x2–4x
allsm [11]

Answer:

x-3x^3

Step-by-step explanation:

^ means to the power of btw

5 0
4 years ago
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
Given that x is an integer, what is the solution of <br>|x-1|<img src="https://tex.z-dn.net/?f=%20%5Cleqslant%201" id="TexFormul
Varvara68 [4.7K]

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | ≤ a always have solutions of the form

- a ≤ x ≤ a

Given

| x - 1 | ≤ 1 then

- 1 ≤ x - 1 ≤ 1 ( add 1 to each of the 3 intervals )

0 ≤ x ≤ 2

Since we require an integer solution then x = 0, 1, 2

5 0
3 years ago
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