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3 years ago

Sec 16° cosec 74° - cot 74° tan 16°

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

Step-by-step explanation:

sec 16° cosec 74° - cot 74° tan 16°

= 1/ cos 16 * 1/ sin 74 - 1/tan 74 * tan16

= 1/ cos16 sin 74 - cos74/ sin74 * sin 16 / cos 16

Now cos 16 = sin 74 and sin 16 = cos 74 (supplementary angles) so:

= 1 / cos^2 16 - sin 16/cos 16 * sin 16 / cos 16

=( 1 - sin ^2 16 )/ cos^2 16

= cos^2 16 / cos^2 16

= 1.

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Sec 16° cosec 74° - cot 74° tan 16°​

Sec 16° cosec 74° - cot 74° tan 16°