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shepuryov [24]
3 years ago
6

Sec 16° cosec 74° - cot 74° tan 16°​

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

1.

Step-by-step explanation:

sec 16° cosec 74° - cot 74° tan 16°​

= 1/ cos 16 * 1/ sin 74 - 1/tan 74 * tan16

= 1/ cos16 sin 74 -  cos74/ sin74 *  sin 16 / cos 16

Now cos 16 = sin 74  and sin 16 = cos 74  (supplementary angles) so:

= 1 / cos^2 16   - sin 16/cos 16 * sin 16 / cos 16

=( 1 - sin ^2 16 )/ cos^2 16

= cos^2 16 / cos^2 16

= 1.

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