Write the equation of a line that goes through the points (4, 8) and (-8, 2)

1 answer:

6 0

First you have to find the slope by subtracting y2 in this case (2) from y1 (8) dividing it over the subtraction of x2 (-8) and x1 (4) then once you get that you pick a point whether it’s (4,8) or (-8,2), plot it using the slope given to you and you’re done.

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Determine dois números ímpares consecutivo cujo produto seja 195

miv72 [106K]

Let 1st integer = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0

We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78
We determine which value of x when substituted gives us a product of 195. 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 The solution is 2 sets of two consecutive number Set 1 The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48
Set 2 The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)

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Alex777 [14]

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Step-by-step explanation:

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Softa [21]

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What is the least common multiple 8 and 12?

Anna35 [415]

Answer:

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∫c x sin y ds, C is the line segment from (0, 1) to (3, 5)

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Parameterize the line segment $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=(1-t)\langle0,1\rangle+t\langle3,5\rangle=\langle3t,1+4t\rangle$

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$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt$
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So the integral is

$\displaystyle\int_Cx\sin y\,\mathrm ds=5\int_0^1x(t)\sin y(t)\,\mathrm dt$
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$=\dfrac{15}{16}(\sin5-\sin-4\cos5)\approx-2.7516$

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3 years ago