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kap26 [50]
3 years ago
10

Label the tick mark and points on the number line.​

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

The answer (from left to right) is -3.5 and -2.5

Step-by-step explanation:

Nimfa-mama [501]3 years ago
3 0

Answer:

from the left to the right: -3.5, -2.5

Step-by-step explanation:

have a good day

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Mr. Hann is trying to decide how many new copies of a book to order for his students. Each book weighs 6ounces
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I’m afraid I can’t help you. The question makes no sense because the question doesn’t explain how many students there are. It just gives the weight of the books which I assume is useless

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3 years ago
Need help on this please
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There is no outlier. :)
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Solve (x + 3)2 – 5 = 0 using the quadratic formula.
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

(x+3)² -5 =0 , use the formula (a+b) ² = a²+b²+2ab

x²+9 +6x -5 =0 , combine like terms

x²+6x +4 =0, use the quadratic formula x = (-b±√b²-4ac)/2a

x= (-6 ±√6²-4*1*4)/2*1

x= (-6 ± √36-16) /2

x= (-6±√20)/2

x=(-6 +2√5)/2 and x=( -6-2√5) /2, factor 2 in the numerator and simplify

x= -3 +√5 and x= -3 -√5

4 0
3 years ago
A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i
yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

T - Ts = (T_0 - Ts)e^k^t

We'll solve for k

35 - 100 = (20 - 100)e^9^k

-65 = (-80)e^9^k

Divide both sides by -5

13 = (16)e^9^k

9k = ln (\frac{13}{16})

k = \frac{1}{9} ln (\frac{13}{16})

k = -0.02307104053

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

T - Ts = (T_0 - Ts)e^k^t

T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100= -52.8125

T = 100 - 52.8125

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0
3 years ago
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