Answer:
Aiden has read 110 pages on day three.
Step-by-step explanation:
Given:
Number of pages he read = 458
Let the number of pages read on Day 1 be
.
Also Given:
On day two,he reads twice the number of pages than he read on day one.
so we can say that;
Number of pages read on Day 2 = ![2x](https://tex.z-dn.net/?f=2x)
Now Given:
On the third day,he reads six pages less than what he read on the first day.
so we say that;
Number of pages read on Day 3 = ![x-6](https://tex.z-dn.net/?f=x-6)
we need to find the Number of pages read on Day 3.
Now we know that;
Total number of pages he read is equal to sum of number of pages read on Day 1, Number of pages read on Day 2 and Number of pages read on Day 3.
framing in equation form we get;
![x+2x+x-6=458\\\\4x-6=458](https://tex.z-dn.net/?f=x%2B2x%2Bx-6%3D458%5C%5C%5C%5C4x-6%3D458)
Adding both side by 6 using Addition property we get;
![4x-6+6=458+6\\\\4x=464](https://tex.z-dn.net/?f=4x-6%2B6%3D458%2B6%5C%5C%5C%5C4x%3D464)
Now By Using Division property we will divide both side by 4 we get;
![\frac{4x}{4}=\frac{464}{4}\\\\x=116 \ pages](https://tex.z-dn.net/?f=%5Cfrac%7B4x%7D%7B4%7D%3D%5Cfrac%7B464%7D%7B4%7D%5C%5C%5C%5Cx%3D116%20%5C%20pages)
Number of pages read on 1 day = 116 pages.
Number of pages read on Day 3 = ![x-6 =116-6 =110\ pages](https://tex.z-dn.net/?f=x-6%20%3D116-6%20%3D110%5C%20pages)
Hence Aiden has read 110 pages on day three.