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3 years ago

Prove that linearly independent set extend to basis

1 answer:

5 0

The completion is certainly not unique. Multiplying any of the new vectors by a nonzero constant will not affect the span or the linear independence, but will change the basis. To prove that you can extend any linearly independent set S to a basis, you proceed by an iterative argument. If S spans you are done. hope this helps :)

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Are these numbers rational or irrational? √10 (square root of 10) √16 (square root of 16) 52% 1.235 1. Rational 2. Irrational pl

77julia77 [94]

Step-by-step explanation:

any rational number can be expressed as a/b, with a and b being integer numbers, and b different to 0.

-7 = -7/1 rational

sqrt(10) irrational (because there is no rational number multiplied by itself that results in 10)

sqrt(16) = sqrt(4×4) = 4 = 4/1 rational

52% = 52/100 rational

1.235 = 1235/1000 rational

5 0

2 years ago

If ƒ(x) = -5n + 1 and g(x) = -6n + 2, find (ƒ + g)(-2).

Stels [109]

(f+g) (n) = (–5n +1 ) + (- 6n +2) = –11n +3

(f+g) (n) = –11n +3

(f+g) (–2) = – 11 (–2) +3 = 22 +3 = 25

I hope I helped you^_^

3 0

3 years ago

(PLEASE HELP ASAP)

lesya [120]

Answer:

Slope: -2
equation: y = -2x +5

Step-by-step explanation:

The given point is the y-intercept of the line, so the slope-intercept form of the equation of a line can be used:

y = mx + b . . . . for slope m and y-intercept b

Here, you have the slope given as ...

m = -2

y-intercept = 5

so the equation of the line is ...

y = -2x +5

_____

The y-intercept is the value of y when x=0. The point (x, y) = (0, 5) tells you the y-intercept is 5.

7 0

2 years ago

Pls help...................

bearhunter [10]

First one b ≤ 9 good luck

5 0

2 years ago

It's Pythagorean theorem

liraira [26]

Answer:

6root3

Step-by-step explanation:

3 0

2 years ago