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Reika [66]
3 years ago
11

What is the y and x intercepts .

Mathematics
1 answer:
hichkok12 [17]3 years ago
4 0

Answer:

y-intercept: (0, -5)

x-intercepts: (-5, 0) , (1, 0)

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1.) (X+9)(x+3)
hodyreva [135]
(x+9)(x+3)=x^2+3x+9x+27=x^2+12x+27\\\\
(y-5)(y^2-2y+6)=y^3-2y^2+6y-5y^2+10y-30=\\
=y^3-7y^2+16y-30
5 0
3 years ago
Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral
MAVERICK [17]

Answer:

a. \frac {2} {s-1} converges to s> 1.

b. \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. - \frac {2}{s + 3} converges to s> - 3.

d. \frac {s}{s^2 + 25} converges to s> 0.

e. \frac {10} {s^2 + 1} converges even s> 0.

f. \frac {12}{s^2 + 4} converges to s> 0.

g. -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. \frac {1} {s ^ 2 + 4} converges to s> 0.

Step-by-step explanation:

a. L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1} converges to s> 1.

b. L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3} converges to s> - 3.

d. L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25} converges to s> 0.

e. L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1} converges even s> 0.

f. L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4} converges to s> 0.

g. L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4} converges to s> 0.

7 0
3 years ago
Hey, I need some help in math I put the pic down below
EastWind [94]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We find the slope with the given points:

m = \frac {y2-y1} {x2-x1} = \frac {401-450} {14-7} = \frac {-49} {7} = - 7

Thus, the line is given by:

y = -7x + b

We substitute a point to find "b":

450 = -7 (7) + b\\450 = -49 + b\\450 + 49 = b\\b = 499

Finally, the equation is:

y = -7x + 499

Answer:

y = -7x + 499

4 0
3 years ago
Translate the product of a number and 4 increased by 1 is -3 into a equation
laiz [17]
4x + 1 = -3

"The product" is the term used to describe the answer of a multiplication equation.
"increased by" means you're adding.
"a number" refers to a variable.
7 0
3 years ago
Which value of n makes the following equation true?
grin007 [14]

Answer: d. 512

Step-by-step explanation:

You need to remember that:

(\sqrt[3]{x})^3=x

Then, given the equation:

\sqrt[3]{n}=8

You can find the value of "n" that make the equation true, by solving for "n".

So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:

 \sqrt[3]{n}=8

 (\sqrt[3]{n})^3=(8)^3

 n=512

Then, the value of "n" that makes the equation \sqrt[3]{n}=8 true is: 512 (You can observe that this matches with the option d).

6 0
3 years ago
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