Answer:
60
Step-by-step explanation:
b = the hypotenuse of a right angle triangle
a = the adjacent side.
R is being defined by the cosine
cos(R) = adjacent / hypotenuse
adjacent = 16* sqrt(2)
hypotenuse = 32*sqrt(2)
Cos(R) = 16*sqrt(2) / 32*sqrt(2) sqrt(2) cancels.
cos(R) = 1/2
R = cos-1(1/2)
R = 60 degrees.
Answer:
42.8 + or - 12
Step-by-step explanation:
He's either gaining or losing $12 so you can write 42.8 plus or minus 12 as the equation
21. 1/7 3/8 1/2
23. 3 5/8 3 3/8 3 1/2
25. 1/6 3/4 2/3
Answer:
The distance between the astronomers and the moon was
meters.
Step-by-step explanation:
We have that the speed is the distance divided by the time, so:

In this problem, we have that:
The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that
.
If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?
We have that
m/s.
We have to find d. So:



![7.56*10^{8]](https://tex.z-dn.net/?f=7.56%2A10%5E%7B8%5D)
The distance between the astronomers and the moon was
meters.
Using Pythagoras theorem
|AB|*2=|d/2|=(5*2)+12*2
AB*2=25+144
AB=13
D/2= r=6.5cm
tan¥=6.5/5
tan¥=1.3
¥=tan inverse of (1.3)
¥=52.43 degrees