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miskamm [114]
3 years ago
8

Each side of a square office is 6 meters long. It will cost $41.00 per square meter to replace

Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

$1,476.00

Step-by-step explanation:

first find area by doing 6*6 which is 36^2 then do 36*41 to get 1476.00

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Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

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2

................ii

form i and ii we can write

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2 years ago
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65 yards because of a2+b2=c2
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Graph x+3y<(or equal to)6, indicating the solution set with cross hatching or shading. Explain how you determine where to dra
Sergeu [11.5K]

Step 1

Given;

x+3y\leq6

Required; To graph the inequality

Step 2

Graph the function

\begin{gathered} We\text{ find the y-intercept by setting x=0} \\ 0+3y\leq6 \\ y\leq2 \\ First\text{ point\lparen0,2\rparen} \end{gathered}\begin{gathered} We\text{ find the x-intercept by setting y=0} \\ x+3(0)\leq6 \\ x\leq6 \\ Secon\text{d point;\lparen6,0\rparen} \end{gathered}

So by finding the x-intercept and y-intercept, we can determine where to draw the line. Since the inequality is greater than or equal to the line will be continuous and not broken. Also, we will know the area we will shade by;

\begin{gathered} Resolving\text{ the inequality and make y the subject of the formular} \\ x+3y\leq6 \\ 3y\leq6-x \\ y\leq2-\frac{x}{3} \end{gathered}

Since if we set x=0, we get y < or equal to 2, then we know that the shaded area will be where y is equal to and below. There we will shade below the point (0,2) to represent the solution set.

8 0
1 year ago
Please help me with this question
jok3333 [9.3K]

9514 1404 393

Answer:

  -3/8 × (first term)

Step-by-step explanation:

The general term of an arithmetic sequence is ...

  an = a1 +d(n -1)

Then the ratio of interest is ...

  (7th term)/(9th term) = 5/8

  (a1 +6d)/(a1 +8d) = 5/8

Multiplying by 8(a1 +8d) we get ...

  8(a1 +6d) = 5(a1 +8d)

  8a1 +48d = 5a1 +40d . . . . . . eliminate parentheses

  8d = -3a1 . . . . . . . . . . . . . . subtract 40d+8a1

  d = (-3/8)a1 . . . . . . . . . . divide by 8 to find the common difference

The common difference is -3/8 times the first term.

__

<u>Example</u>

Let the first term be -16. Then the common difference is (-3/8)(-16) = 6. The first 9 terms of the sequence are ...

  -16, -10, -4, 2, 8, 14, 20, 26, 32

The ratio of the 7th and 9th terms is ...

  20/32 = 5/8 . . . . as required

__

In the general case, the ratio of terms would be ...

  (a1 +(-3/8a1)(7 -1))/(a1 +(-3/8a1)(9 -1)) = (1 -6(3/8))/(1 -8(3/8)) = (-10/8)/(-16/8) = 5/8

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