Answer:
The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.
Step-by-step explanation:
Given,
CGPA = 2.75
Credit hours = 105
Last semester GPA = 4
Last semester credit hours = 15
CGPA = 
credit hours * gpa
in our case, it would be:
CGPA = 
=> 
=> 
=> 2.90
The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.
Answer:
204xy^(3)
Step-by-step explanation:
Step-by-step explanation:
p<5 that's the answer for the question
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.
n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10 OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK
n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42
So the answer is B
D. The males have a suspected significant high outlier.
The outlier will make the box plot be uneven and this will affect the spread and the center.
I know isn't A, because if anything that would make it more balanced.
I know it isn't B because this would not affect the spread or the center.
I know it isn't C because the question is not asking you to determine the spread and center, just to see if there is anything that would affect them.
I hope this helps!
