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3 years ago

10

Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than t

wo times the width
PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS HELP

1 answer:

crimeas [40]3 years ago

3 0

ALGEBRA M8 SOZ

Length = L, Width = W

L = 20 + 2W,
2L + 2W = 610.

then u gotta do some inspiring expression-algebra-maths stuff to work it out :)

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