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sergij07 [2.7K]
3 years ago
5

Pls help me i need help with this

Mathematics
1 answer:
Rudiy273 years ago
7 0

my answer is in this picture.

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Explain how to find coordinates for Q
Vesna [10]

Answer:

Q = (4, - 1)

Step-by-step explanation:

DF is the diameter of the circle with center Q.

So, Q is the midpoint of DF.

By mid point formula.

Q =  \bigg( \frac{1 + 7}{2},  \:  \:  \frac{3 - 5}{2} \bigg) \\  \\ Q =  \bigg( \frac{8}{2},  \:  \:  \frac{ - 2}{2} \bigg) \\  \\ Q = (4, \:  \:  - 1)

6 0
3 years ago
Read 2 more answers
1/4 (-12+3) -8/3<br> Simplified
labwork [276]

Answer:

-59/12

Step-by-step explanation:

finish whats inSide brackets first

so -12+3 =-9

-9*1/4 will be next and = -9/4

9/4+8/3 =. 59 /12

6 0
3 years ago
I dont understand please help Which expression is equivalent to 8-(6r+2) A -6r+6 B 2r+2 C 6r+10 D -6r+10
Goryan [66]

Answer:

-6r+6

Step-by-step explanation:

Given data

We are given the expression

8-(6r+2)

let us expand it by opening the bracket

=8-6r-2

collect like terms

=8-2-6r

=6-6r

rearrange

=-6r+6

Hence option A is correct

8 0
3 years ago
Find the third side in simplest radical form:<br> 25
Gre4nikov [31]

Answer:

<h3>\boxed{  \bold{24}}</h3>

Step-by-step explanation:

\mathsf{given}

\mathsf{hypotenuse(h) = 25}

\sf{perpendicular (p) = 7}

\sf{base(b) = }?

Now, Using Pythagoras theorem

\sf{{h}^{2}  =  {p}^{2}  +  {b}^{2} }

plug the values

⇒\sf{  {25}^{2}  =  {7}^{2}  +  {b}^{2} }

Evaluate the power

⇒\sf{625 = 49 +  {b}^{2} }

Swap the sides of the equation

⇒\sf{49 +  {b}^{2}  = 625}

Move constant to right hand side and change it's sign

⇒\sf{ {b}^{2}  = 625 - 49}

Calculate the difference

⇒\sf{ {b}^{2}  = 576}

Squaring on both sides

⇒\sf{b = 24}

Hope I helped!

Best regards!

8 0
4 years ago
THIS IS URGENT PLEASE
Naya [18.7K]

Answer:

5

Step-by-step explanation:

The side with 4 cubes has a length of 2, the side with 2 cubes has a length of 1, and the side with 5 cubes has a length of 2.5.

2 x 1 x 2.5 = 5

4 0
3 years ago
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