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patriot [66]
3 years ago
8

Solve for x: 2|x − 3| + 1 = 7

Mathematics
1 answer:
bearhunter [10]3 years ago
6 0
***SOLVE FOR X***


Answer:<span><span>
x=<span><span>6<span> or </span></span>x</span></span>=<span>0</span></span>
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Evaluate the expression for a = 5, b = 11, and c = 3. 2a + 2c(b − 5) A. 64 B. 46 C. 54 D. 163
Artemon [7]

2a +2c(b-5)

substitute a=5 b=11 c=3

2(5) +2(3) (11-5)

10+6(6)

10+36

46

Choice B


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2 years ago
Heelp will give brianliest
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256

Step-by-step explanation:

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196 + 60 = 256

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3 years ago
Express the area of the entire rectangle.
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3 years ago
Find the area of the shaded region ​
o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)

A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill

\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}

5 0
2 years ago
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