Probbality=desired outcomes/total possible outcomes
so you and 2 friends makes 3 people
you each order a differnt topping
so
7/14 or 1/2 of them are meat on first try
then, 1 less topping, so 6/14 or 3/7 are meat for 2nd peson
then 1 less topping so 5/14 are meat for 3rd person
1/2 times 3/7 times 5/14=15/196
probablity will be 15/196 or about 7.65%
Answer:
C
Step-by-step explanation
Why does C work:
You can calculate the rate of change by subtracting 12 from Distance Traveled = 1, from 12.75 from Distance Traveled = 2 to find the difference of 0.75.
Because the multiple-choice only offers fractions you can check if .75 is correct by converting it into a fraction. This is true, 0.75 is equal to 3/4.
Now that you know the rate of change you need to find the initial value which would be Distance Traveled = 0 and Time = __. To find this you subtract 0.75 from 12 which would give you 11.25.
C. y = 3/4(0.75) + 11.25
Answer:
If n = 1000000, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If n = 10400, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If N = 102, then

Step-by-step explanation:
Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2
The density function of that random variable is given by de following formula

If n = 1000000, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If n = 10400, then
![P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk](https://tex.z-dn.net/?f=P%28h%20E%20%5B495000%2C%20505000%5D%29%20%3D%20%5Cint%5Climits%5E%7B50500%7D_%7B495000%7D%20%7B%5Cfrac%7B2%7D%7B%5Csqrt%7B2000000%5Cpi%7D%7D%20e%5E%7B%5Cfrac%7B-%28k-500000%29%5E2%7D%7B500000%7D%20%7D%7D%20%5C%2C%20dk)
If N = 102, then

Answer:
20
25
10
Step-by-step explanation:
Answer:
12 milkshake can be made by 1/3 cup
1 milkshake can be made by (1/3)/12 cup
72 milkshake can be made by ((1/3)/12)*72 cup = 2cup
Step-by-step explanation: