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Phantasy [73]
3 years ago
13

Mr. Clarke built a deck around the swimming pool and sandbox in his backyard. What is the area of the decking that surrounds the

pool and sandbox, rounded to the nearest tenth of a square foot?

Mathematics
1 answer:
ss7ja [257]3 years ago
4 0

Answer:

1,174.8\ ft^{2}

Step-by-step explanation:

we know that

The area of the decking is equal to the area of the parallelogram minus the area of the pool minus the area of the sand box

Remember that

21\frac{1}{2}\ ft=21.5\ ft

so

A=(50)(35)-(20)(25)-(21.5)(7)/2\\A= 1,750-500-75.25\\A=1,174.8\ ft^{2}

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