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Anvisha [2.4K]
3 years ago
7

HELP, it’s question 17

Mathematics
2 answers:
Dovator [93]3 years ago
8 0

Answer: A

Step-by-step explanation:

snow_lady [41]3 years ago
7 0

Answer:

1/3 of 60 = 20

2/5 x 3 = 1 1/5

A: 1 1/5 cans of paint

Step-by-step explanation:

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Megan hiked 15.12 miles in 6.3 hours. If Megan hiked the same number of miles each hour, how many miles did she hike each hour?
kifflom [539]
15.12 miles/ 6.3 hours= 2.4 miles/hour.

The final answer is 2.4 miles per hour~
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3 years ago
El triángulo que usamos en las funciones trigonométricas es
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Trigonometric functions are commonly defined as the quotient between two sides of a right triangle, associated with its angles. Trigonometric functions are functions whose values are extensions of the trigonometric reason concept in a right triangle plotted in a unit circumference (radius unit).

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3 years ago
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What Is The Average Of 4,4 And 5
velikii [3]

Answer:

The answer is B, 4 and 1/3

Step-by-step explanation:

4+4+5 divided by three is 4 and 1/3.

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3 years ago
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Steven just got a new summer job painting fences in his neighborhood. He will be paid $7.25 an hour. His first customer paid him
aliya0001 [1]

Answer:

Part A: 7.25x = 36.25

Part B: 5 hours

Step-by-step explanation:

36.25/7.25 = 5

8 0
3 years ago
The sum of the first 10 terms of an arithmetic series is 100 and the sum of next 10 300 .Find the series.​
Free_Kalibri [48]

Let a be the first term in the sequence, and d the common difference between consecutive terms. If aₙ denotes the n-th term in the sequence, then

a₁ = a

a₂ = a₁ + d = a + d

a₃ = a₂ + d = a + 2d

a₄ = a₃ + d = a + 3d

and so on, up to the n-th term

aₙ = a + (n - 1) d

The sum of the first 10 terms is 100, and so

\displaystyle \sum_{n=1}^{10} a_n = 100 \\ \sum_{n=1}^{10} (a + (n-1)d) = 100 \\ (a-d) \sum_{n=1}^{10} 1 + d \sum_{n=1}^{10} n = 100 \\ 10a+45d = 100

where we use the well-known sum formulas,

\displaystyle \sum_{n=1}^N 1 = 1 + 1 + 1 + \cdots + 1 = N

\displaystyle \sum_{n=1}^N n = 1 + 2 + 3 + \cdots + N = \frac{N(N+1)}2

The sum of the next 10 terms is 300, so

\displaystyle \sum_{n=11}^{20} a_n = 300 \\ (a-d) \sum_{n=11}^{20} 1 + d \sum_{n=11}^{20} n = 300 \\ (a-d) \left(\sum_{n=1}^{20} 1 - \sum_{n=1}^{10} 1\right) 1 + d \left(\sum_{n=1}^{20} n - \sum_{n=1}^{10} n\right) = 300 \\ 10a+145d = 300

Solve for a and d. Eliminating a gives

(10a + 145d) - (10a + 45d) = 300 - 100

100d = 200

d = 2

and solving for a gives

10a + 145×2 = 300

10a = 10

a = 1

So, the given sequence is simply the sequence of positive odd integers,

{1, 3, 5, 7, 9, …}

given recursively by the relation

\begin{cases}a_1 = 1 \\ a_n = a_{n-1} + 2 & \text{for }n>1\end{cases}

and explicitly by

a_n = 1 + 2(n-1) = 2n - 1

for n ≥ 1.

7 0
2 years ago
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