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oee [108]
2 years ago
7

PLSSSSSSS HELP ME WITH THESE FOUR QUESTIONS (•‿•)

Mathematics
2 answers:
LenaWriter [7]2 years ago
5 0

Answer:

1. C

2. A

3. C

4. A

Step-by-step explanation:

ANTONII [103]2 years ago
4 0
Q1- Right 3 Down 9
Q2- Left 9 Down 9
Q3- Up 6
Q4- Up 18
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The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer
AlladinOne [14]

Answer:

4-2.326\frac{1}{\sqrt{100}}=3.767    

4+2.326\frac{1}{\sqrt{100}}=4.233    

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=4 represent the sample mean

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=100 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that z_{\alpha/2}=2.326

Now we have everything in order to replace into formula (1):

4-2.326\frac{1}{\sqrt{100}}=3.767    

4+2.326\frac{1}{\sqrt{100}}=4.233    

So on this case the 98% confidence interval would be given by (3.767;4.233)

   

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2 years ago
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Step-by-step explanation:

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