Answer:
Step-by-step explanation:
3c + 5w = 16
6c + 2w = 22
-6c - 10w = -32
6c + 2w = 22
-8w = -10
w = 10/8 = 5/4 = $1.25 per lb
3c + 5(1.25) = 16
3c + 6.25 = 16
3c = 9.75
c = $3.25 per lb
Answer:
Step-by-step explanation:
You can readily see from the diagram, above, that the side length of the middle cube will be between 3 and 4. You want to determine to the nearest hundredth what value between 3 and 4 represents the side length of the cube whose volume is 45 units^3.
Please note: the middle cube has been mislabeled. Instead of volume = 30 units^3, the volume should be 45 units^3.
Here's the procedure:
Guess an appropriate s value. Let's try s = side length = 3.5
Cube this: (3.5 units)^3 = 42.875. Too small. Choose a larger possible side length, such as 3.7: 3.7^3 = 50.653. Too large.
Try s = 3.6: 3.6^3 = 46.66. Too large.
Choose a smaller s, one between 3.5 and 3.6: 3.55^3 = 44.73. This is the best estimate yet for s. Continue this work just a little further. Try s = 3.57. Cube it. How close is the result to 45 cubic units?
Answer:
corresponding angles because it is in a F pattern shape
always corresponding angle is denoted from F pattern and its sum is always equal
Answer:
Both situations have the same rate of change
3 miles/hr
Step-by-step explanation:
situation 1
"3 miles in one hour" = 3 miles/hr
situation 2
"6 miles in two hours" = 6 miles / 2 hours =6/2 miles/hr = 3 miles./hr
Hence both are the same
Answer:
The worth of car at the start of 2014 = $12000
The value of the car decreased 30% every year.
At start of 2015:
30% of 12000 = \frac{30}{100} \times 12000
100
30
×12000 = 3600
So, the value of the car at start of 2015 = 12000-3600 = $8400.
At start of 2016:
30% of 8400 = \frac{30}{100} \times
8400
100
30
×8400 = 2520
So, the value of the car at start of 2016 = 8400-2520 = $5880.
At start of 2017:
30% of 5880 = \frac{30}{100} \times
5880
100
30
×5880 = 1764
the value of the car at start of 2017 = 5880-1764 = $4116.
So, the value of his car at the start of 2017 is $4116.
