Answer:
I think A and B as they both have 27- degree angles
Step-by-step explanation:
I MAY BE WRONG SORRY
Answer:
The graph is shown below.
Step-by-step explanation:
The trigonometric expression is:
The general form is:
Comparing the two expression we know:
a = 1
b = 1
c = 0
d = -5
Compute the value of amplitude, |<em>a </em>| as follows:
Compute the period of the function as follows:
Compute the phase shift as follows:
The vertical shift is:
The properties of the trigonometric function are:
Amplitude = 1
Period = 2π
Phase shift = 0
Vertical shift = -5
Plot the graph of the trigonometric function by selecting a few points.
<em> x</em> :
f (<em>x</em>) : -5 -4 -5 -6 -5
The graph is shown below.
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Answer:
f⁻¹(x) = log(x)/log(16)
g⁻¹(x) = (2^x -1)/3
Step-by-step explanation:
In each case, you want to solve ...
x = f(y)
__
a. x = 4^(2y)
log(x) = 2y·log(4) . . . . . . . . take logs
y = log(x)/(2·log(4)) . . . . . . .divide by the coefficient of y
f⁻¹(x) = log(x)/log(16) . . . . simplify (4^2 = 16)
__
b. x = g(y)
x = log(3y +1)/log(2) . . . . use the change of base relation
x·log(2) = log(3y +1) . . . . multiply by log(2)
2^x = 3y +1 . . . . . . . . . . . take antilogs
2^x -1 = 3y . . . . . . . . . . . subtract 1
y = (2^x -1)/3 . . . . . . . . . . divide by the coefficient of y
g⁻¹(x) = (2^x -1)/3 . . . . . . . . note that "-1" is not part of the exponent of 2
Answer:
Use Pythagorean.
The triangles have sides 2, 5 and c.