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goldenfox [79]
2 years ago
12

Which is the answer?

Mathematics
1 answer:
Tom [10]2 years ago
8 0

Answer:

y=3x

Step-by-step explanation:

y=3x is the one according to values in the table

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Expand and simplify (3x+5)(4x-1)
Whitepunk [10]
Use FOIL and simply, First times First, Outside times Outside, Inside times Inside, Last times Last.

(3x+5)(4x-1)
3x * 4x = 12x²
3x * -1 = -3x
5 * 4x = 20x
5 * -1 = -5

12x² - 3x + 20x - 5

Now simplify by adding -3x to 20x and get:

12x² + 17x - 5
5 0
2 years ago
Please help with this one!!
rodikova [14]
Associative property is a+(b+c)=(a+b)+c

step1 is commutative property of addition
2nd step is associative property of addition
3rd step is distributive property
4th step is mutliplication or associative property of multiplication
7 0
3 years ago
Use the balanced scale to find the conversion factor that can be used to convert the number of blocks to the weight of the block
Sedbober [7]

Answer:

A. 1.5 pounds per block

Step-by-step explanation:

The conversion factor shows 2 blocks on the right and three 1 pound blocks on the left. It takes two 1 pound blocks to make 2 and then you get your 3rd block, making it 3 (.5 more than 2.5) needing another block to add a .5

8 0
2 years ago
Read 2 more answers
IF you are in 5th K12 I really need help and if you know the answer them answer
ratelena [41]

Answer:

=0.013793

Step-by-step explanation:

hope i helped

3 0
3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
1 year ago
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