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MrMuchimi
3 years ago
8

Inequalities!! please help!!

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

x=24

Step-by-step explanation:

$;$"+";$;";";'+$-$$+$+$+_+

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154= -4(8 + 6x) + 24x
icang [17]
154=-32-24x+24
154+32-24=-24x
162=-24x
162/-24=-24x/-24
X=-6.75
7 0
3 years ago
i have a problem im struggling with it says. is 6 a solution to the equation x2 - 4=5x explain why or why not?
Eddi Din [679]

Answer:

No, 6 is not a solution to the equation x2-4=5x

Step-by-step explanation:

6(2)-4=5(6)

12-4=30

8=30

The question is basically asking if you replace x with 6, will the equation equal each other on both sides, for example 6=6 or 3.5=3 1/2. In this case the equation gives us 8=30 which means 6 would not be a solution since both sides aren't equal to one another, 30 is bigger than 8.

6 0
4 years ago
All the numbers from 1 to 100 that have 13 as a factor
Marrrta [24]
26, 39, 52, 65, 78, 91
3 0
4 years ago
Find the area of the trapezoid. Leave your answer in simplest radical form.
sveticcg [70]

Answer:

64√3 ft²

Step-by-step explanation:

The short leg of the triangle has length (8 ft)(cos 60°), or (8 ft)(1/2), or 4 ft.

The long leg (represented by the dashed line) is (8 ft)(sin 60°), or

(8 ft)(√3/2), or 4√3.  This is also the width of the horizontal trapezoid.

The area of this horizontal trapezoid is:

      (sum of horizontal sides)

A = ------------------------------------- * (width)

                         2

Here, the area is:

      (18 ft + (18 ft - 4 ft)

= ------------------------------------- * (4√3)

                   2

    32 ft

= ----------- * 4√3  =  64√3 ft²

       2

5 0
3 years ago
Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an
lyudmila [28]
<h2>Answer:</h2>

Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°


<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°


So the components can be found as follows:

F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf


So the components of the resultant force can be found by adding each component of the individual forces as follows:

R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf


Finally, the magnitude and direction of the resultant force is:

Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees

6 0
3 years ago
Read 2 more answers
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