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2 years ago

Please help im desperate :)

Mathematics

1 answer:

kupik [55]2 years ago

4 0

Answer:

-2

Step-by-step explanation:

You can see that the line is passing through the negative point, which is -2.

I hope this helped!

~natasha

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3 years ago

What is the apparent slope of the line graphed below

maria [59]

I think the answer would be -2.5 because 0-5=-5 and 4-2=2 you subtract the perfect points X1-x2 with y2-y1

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3 years ago

Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.

Elden [556K]

Answer:

( 6(x)² + 12(x) - 90 ) ft³

Explanation:

deep end water: 2(x)² + 12(x) + 10

shallow end water: 4(x)² - 100

addition problem: 2(x)² + 12(x) + 10 + 4(x)² - 100

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2(x)² + 12(x) + 10 + 4(x)² - 100

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2 years ago

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Marizza181 [45]

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2 years ago

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Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes

lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 680 trials

r = number of success

p = probability of success which in our question is 0.55

So, it means X ~ $Binom(n=680, p=0.55)$

Now, we have to find the mean and standard deviation of the given binomial distribution.

Mean of Binomial Distribution is given by;

E(X) = n $\times$ p

So, E(X) = 680 $\times$ 0.55 = 374

Standard deviation of Binomial Distribution is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{680 \times 0.55 \times (1-0.55)}$

= $\sqrt{680 \times 0.55 \times 0.45}$ = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

3 0

3 years ago

Please help im desperate :)​

Please help im desperate :)