You need to turn 1/2 to .5 and 3/4 to .75 then you use this equation.
75% * 950,000 (profit)
+ 25% * -285,000 (loss)
<span>= then you subtract the numbers from the separate </span>
<span>= answer --> expected profit from the second mall</span>
√x + 11=15 x=16
√x= 15-11 x=16
To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer:
2<x<3
Step-by-step explanation:
4x-4<8 AND 9x+5>23
Solve the first inequality
4x-4<8
Add 4 to each side
4x-4+4 <8+4
4x<12
Divide by 4
4x/4 <12/4
x <3
Solve the second inequality
9x+5>23
Subtract 5 from each side
9x+5-5>23-5
9x >18
Divide by 9
9x/9>18/9
x>2
Put together
x<3 and x>2
2<x<3
Answer:
f(x)=x^2
Step-by-step explanation:
if you wanted have a function where both of the robot's arms are in the air the function could be x to the power of any even number such f(x)=x^2, f(x)=x^4, f(x)=x^6, or even f(x)=x^10. And you could still do the same transformations with these equations.
