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valentinak56 [21]
3 years ago
10

I need help with these

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

Step-by-step explanation:

5)               -7 (-15w + 21) + 3(18 - 27w)

Step 2:        105w - 81w - 147 + 54

6)      

step 3:       24w - 93

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Java 1
KatRina [158]

Answer:

Q20     b.16

Q21      a.6

Step-by-step explanation:

count charcters  Have a nice day!  ==16

Q21    why 6

because index start with 0 and not 1

just count

H ==> 0

e==> 1

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W=>6

6 0
3 years ago
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jarptica [38.1K]

Answer:

20 student who have a screen time of 12 or more hours have a grade below 80

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Step-by-step explanation:

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3 years ago
Point D is the in center of triangle ABC. Write an expression for the length x in terms of the three side lengths AB, AC, BC.
shutvik [7]

Answer :

\underline{ \boxed{x =  \frac{2(A_T) }{(AB)  +  (AC) + (BC)} }}

Explanation :

i \: figured \: it \: out \to \: notice \: that \\ there \: are \:( thre e\: trianges) \: in \: triangle  \: ( ABC) \\ and \: they \: all \: have \: the \: same \: height \:  = x \\ first \: triangle \: is \:  \to \: triangle \: (ABD) \\ second\: triangle \: is \:  \to \: triangle \: (ACD) \\ third \: triangle \: is \:  \to \: triangle \: (BCD) \\ if \: the \: area \: of \: a \: triangle \: is \:  =  \frac{1}{2} bh  : then  \to \\ the \: area \: of \: triangle \: (ABD)  =  \frac{1}{2} (AB)x \\ the \: area \: of \: triangle \: (ACD)  =  \frac{1}{2} (AC)x \\ the \: area \: of \: triangle \: (BCD)  =  \frac{1}{2} (BC)x \\ let \: the \: total \: area \:(A_T) \: be \to \: \frac{1}{2} (AB)x  +  \frac{1}{2} (AC)x + \frac{1}{2} (BC)x  \\  if \to\\ (A_T)  =  \frac{1}{2} (AB)x  +  \frac{1}{2} (AC)x + \frac{1}{2} (BC)x   \\ then \to \\ (A_T)  =  \frac{1}{2}  \{(AB)x  +  (AC)x + (BC)x  \} \\ x  \{(AB)  +  (AC) + (BC)  \} = 2(A_T)  \\ x =  \frac{2(A_T) }{(AB)  +  (AC) + (BC)}

3 0
3 years ago
Use the slope formula to find the slope of the line through the points (−1,−1) and (−2,−2).
lozanna [386]

Answer: The slope is 1

Step-by-step explanation:

The slope formula is (y2 - y1)/(x2-x1)

Plugging in these values, we get (-2 - (-1))/(-2 - (-1)), or -1/-1, or simply 1.

Hope it helps :)

6 0
3 years ago
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