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ehidna [41]
3 years ago
6

The ordered pair below is a solution to which equation? (40, 5)

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
6 0
All we have to do here is to express numbers 40 and 5 in each of equations. Note that first number in brackets is always x coordinate and second number is y coordinate

First equation:
5 = 40*8  false

Second
5 = 5*40 false again

Third:
5 = 40/8 = 5 True

checking for just in case last one:
5 = 40/5 = 8 False

Correct one is C)
meriva3 years ago
6 0
C. y =1/8x
because 5=(1/8)(40)
5=5
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Answer:

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Step-by-step explanation:

Rearrange, find common denominator.

x =  \frac{7}{8}  -  \frac{1}{2}  \\ x =  \frac{7}{8}  -  \frac{4}{8}  \\ x =  \frac{3}{8}

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Answer:

soln

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Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
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Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

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Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
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