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Sergio039 [100]
3 years ago
5

I NEED HELP WITH THIS!

Mathematics
1 answer:
gogolik [260]3 years ago
6 0

Answer:

Not enough information

Step-by-step explanation:

There is no limit to how many figures you can create. There is not enough information to solve this. If this is only a part of the question, try to include all of it.

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The answer will be 45 because once you divide all the numbers you will get 45
Hope this helps
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A regular 10-sided polygon is called a decagon. What is the area of the decagon that has sides that measure 4.5 inches and an ap
scoray [572]

Answer:

94.5 square inches :)

Step-by-step explanation:

3 0
4 years ago
Urgent answer with steps
exis [7]
It is a positive correlation because the weight of the puppy increases as the days increase
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3 years ago
ANSWER ASAP PLZ!!
Vikentia [17]

\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}

Answer:

\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}

0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}

--------------------------------------------------------------------------

\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right

Answer:

\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}

2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}

7 0
4 years ago
In the image below, what is the scale factor that would take the right polygon onto the left polygon?
ale4655 [162]

Step-by-step explanation:

You don't have an image so it's diffcult to answer the question I'll help but I need the image please and thank you

4 0
3 years ago
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