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kifflom [539]
2 years ago
7

∠A and ∠ B ∠B are complementary angles. If m ∠ A = ( x − 23 ) ∘ ∠A=(x−23) ∘ and m ∠ B = ( 2 x + 29 ) ∘ ∠B=(2x+29) ∘ , then find

the measure of ∠ B ∠B
Mathematics
1 answer:
Dafna1 [17]2 years ago
8 0

Answer:

85

Step-by-step explanation:

2x + 29 + x - 23 = 180

solve for x = 28

b = 2 * 28 + 29 = 85

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Could you please provide the equation and the rest of the question?
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Are you able to write?
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Estimate the solution to the system of equations. 7x−y=7<br><br> x+2y=6<br> ​
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Answer:

I am not sure how your teacher wanted you to estimate the answer but I solved it for you. Hopefully this helps.

Step-by-step explanation:

7x-y=7

x+2y=6

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x+2y=6

add both equations

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3 0
3 years ago
A 11 inch by 8 inch piece of cardboard squares cut out of the corners and is folded up to make up an open-top-box. If the volume
Arada [10]
<h3>Answer:  b. either 2.5 inches or about .716 inches</h3>

=====================================================

Work Shown:

I have attached two images below. The first shows figures 1 through 4. The second image shows figure 5.

Start with figure 1. Work your way left to right, top to bottom til you get to figure 4. This is the basic process to turn a flat piece of cardboard into a 3D folded box.

The dashed lines in figure 1 are x inches long.

Figure 2 is the result of cutting out the dashed lines you see in figure 1.

When you fold along the dashed lines in figure 2, you'll end up with something similar to figure 3.

Figure 4 is the completed open-top-box. In other words, this box does not have a lid.

The green portions in figures 3 and 4 indicate where the flaps used to be in reference to figure 2.

-------------------

Since those dashed lines in figure 1 were x inches long, this means that the distance from A to B is 11-x-x = 11-2x inches long.

This makes segment BD to be 8-2x inches long. We are subtracting off 2 copies of x each time for each dimension.

------------------

length = AB = 11-2x

width = BD = 8-2x

Since we want the length to be positive, this means 11-2x > 0 which solves to x < 5.5

Since we want the width to be positive, this means 8-2x > 0 which solves to x < 4

Overall, we must make x < 4 to make both inequalities 11-2x > 0 and 8-2x > 0 to be true at the same time.

Furthermore, x is some length itself, so it cannot be negative either. Therefore x > 0 or 0 < x

Combine 0 < x and x < 4 to get 0 < x < 4

The restriction 0 < x < 4 will be used later.

------------------

For now, let's compute the volume.

Volume = Length*Width*Height

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x = 0.716 (shown as point A)

x = 2.5 (point B)

x = 6.284 (point C)

Recall that earlier we made 0 < x < 4. The first two roots satisfy this inequality, but x = 6.284 is outside this range. So we ignore it. It looks like your teacher put 6.284 as a trick answer in choice A.

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