Question

Convert this quadratic to vertex form f(x)=(x-h)^2+k by completing the square. 3x^2-6x+6=0

Answer 1

$f(x)=3x^2-6x+6\\\\f(x)=3(x^2-2x)+6\\\\f(x)=3(\underbrace{x^2-2x+1}-1)+6\\\\ f(x)=3[(x-1)^2-1]+6\\\\f(x)=3(x-1)^2-3+6\\\\f(x)=3(x-1)^2+3$