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3 years ago

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Mathematics

2 answers:

Feliz [49]3 years ago

8 0

I can't see what the question is, everything appears blank ... Sorry

pashok25 [27]3 years ago

3 0

Answer:

uhhh wheres the question

Step-by-step explanation:

You might be interested in

Charlie and Daniella each began a fitness programme. On day one, they both ran 500m. On each subsequent day, Charlie ran 100m mo

alukav5142 [94]

Answer:

a) 2400m on the 20th day for Charlie.

1) 728.41m of 20th day for Daniella.

Didn't find n, sorry.

8 0

3 years ago

What is the determinant of 15 18 154

IgorC [24]

Answer:

The determinant is 15.

Step-by-step explanation:

You need to calculate the determinant of the given matrix.

1. Subtract column 3 multiplied by 3 from column 1 (C1=C1−(3)C3):

$\left[\begin{array}{ccc}-25&-23&9\\0&3&1\\-5&5&3\end{array}\right]$

2. Subtract column 3 multiplied by 3 from column 2 (C2=C2−(3)C3):

$\left[\begin{array}{ccc}-25&-23&9\\0&0&1\\-5&-4&3\end{array}\right]$

3. Expand along the row 2: (See attached picture).

We get that the answer is 15. The determinant is 15.

6 0

3 years ago

Sonya expected to get $60 for her birthday ,but she only got $40.What was the percentage decrease of the amount Sonya recieved?

kow [346]

Are you asking about the percent of change?if so the answer is 33.3%.

7 0

3 years ago

Read 2 more answers

a town has a population of 16000 and grows at 2% every year. to the nearest tenth of a year, how long will it be until the popu

miss Akunina [59]

20100 = 16000 * (1.02)^ t

20100/16000 = 1.02^t

1.25625 = 1.02^t

log 1.25625 = t * log 1.02

t = log 1.25625 / log 1.02
= 11.5

8 0

2 years ago

Read 2 more answers

The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl

koban [17]

Answer:

98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list

(0.3583 , 0.4579)

Step-by-step explanation:

Explanation:-

Given sample size 'n' = 517

Given data Suppose a sample of 517 suspected criminals is drawn. Of these people, 211 were captured.

'x' =211

The sample proportion

$p^{-} = \frac{x}{n} = \frac{211}{517} =0.4081$

$q^{-} = 1-p^{-} = 1- 0.4081 = 0.5919$

98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list

$(p^{-} - Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} )}{n} } , p^{-} + Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} }{n} } )$

$(0.4081 - 2.326 \sqrt{\frac{0.4081 (0.5919 )}{517} } , 0.4081+ 2.326\sqrt{\frac{0.4081(0.5919 }{517} } )$

(0.4081-0.0498 , 0.4081 +0.0498)

(0.3583 , 0.4579)

Conclusion:-

98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list

(0.3583 , 0.4579)

7 0

3 years ago