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Mrac [35]
2 years ago
9

HELPPPPP MEEEE PLEASE

Mathematics
2 answers:
Arte-miy333 [17]2 years ago
8 0

Answer: -6

Step-by-step explanation: dont forget to mark me as brainlisit

zalisa [80]2 years ago
5 0

Answer: -6 i think

Step-by-step explanation:

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Solve <br><img src="https://tex.z-dn.net/?f=2x%20%2B%205%20%3D%2012" id="TexFormula1" title="2x + 5 = 12" alt="2x + 5 = 12" alig
VMariaS [17]

Answer:

x=3.5

Step-by-step explanation:

subract 5 on the other side, than divide by 2

8 0
2 years ago
A house worth £80,000 in January 2012 is set to decrease in value by 7% per year.
kramer
The answer would be 59,844 or around that number
7 0
3 years ago
Can someone please help me and explain​
Fiesta28 [93]

Answer:

0.23

Step-by-step explanation:

3 0
2 years ago
This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0
2 years ago
At the start of the diet keirin weighted 14 stone 13 pounds three months later he weighted 13 stone 10 pounds there are 14 pound
WINSTONCH [101]

Answer:

The amount of weight he has lost in 3 months is 1.215 stone or 1 stone 3 pounds

Step-by-step explanation:

From the above question, we are to calculate the amount of weight he has lost in three months

1 stone = 14 pounds

Let's convert all the weight lost to stone

At the start of the diet keirin weighted 14 stone 13 pounds

14 pounds = 1 stone

13 pounds = x

Cross Multiply

14x = 13

x = 13/14

x = 0.9285714286 stone

Approximately = 0.929 stone

Hence:

14 stone 13 pounds = 14 + 0.929 = 14.929 stone

Three months later he weighted 13 stone 10 pounds

14 pounds = 1 stone

10pounds = x

Cross Multiply

14x = 10

x = 10/14

x = 0.7142857143 stone

Approximately = 0.714 stone

Hence:

13 stone 10 pounds = 13 + 0.714 = 13.714 stone

The amount of weight he has lost is calculated as:

14.929 stone - 13.714 stone = 1.215 stone or 1 stone 3 pounds

5 0
2 years ago
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