Answer :
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Step-by-step-explanation :
Write 11:49 A.M in 24-hour time format. Please PLEASE someone help me!!
2 answers:
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Answer:
Null Hypothesis, : p = 0.20
Alternate Hypothesis, : p > 0.20
Step-by-step explanation:
We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.
We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.
<em>Let p = population proportion of users who develop nausea</em>
So, <u>Null Hypothesis,</u> : p = 0.20
<u>Alternate Hypothesis</u>, : p > 0.20
Here, <u><em>null hypothesis</em></u> states that 20% of users develop nausea.
And <u><em>alternate hypothesis</em></u> states that more than 20% of users develop nausea.
The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.
T.S. = ~ N(0,1)
where, = proportion of users who develop nausea in a sample of 241 subjects =
n = sample of subjects = 241
So, the above hypothesis would be appropriate to conduct the test.
Answer:
The number of students who took English and History, but not Math is 143.
Step-by-step explanation:
Denote the subject choices as follows:
<em>M</em> = a students was taking Math
<em>E</em> = a students was taking English
<em>H</em> = a students was taking History
The data provided is as follows:
N (M) = 257
N (E) = 282
N (H) = 323
n (M ∩ E) = 154
n (M ∩ H) = 171
n (E ∩ H) = 143
n (M ∩ E ∩ H) = 80
Consider the Venn diagram below.
From the provided data and the Venn diagram the value of the set E and H minus M is 143.
Thus, the number of students who took English and History, but not Math is 143.
