Probability that the student got a 'C' GIVEN they are female = number of females that got a C in the test/number of females
From the information given,
number of females that got a C in the test = 12
number of females = 30
Thus,
Probability that the student got a 'C' GIVEN they are female = 12/30
We would simplify the fraction by dividing the numerator and denominator by 6. Thus,
Probability that the student got a 'C' GIVEN they are female = 2/5
Answer:
true
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 8
p2 - 2p + 8p - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
p • (p-2)
Add up the last 2 terms, pulling out common factors :
8 • (p-2)
Step-5 : Add up the four terms of step 4 :
(p+8) • (p-2)
Which is the desired factorization
Answer: Last option.
Step-by-step explanation:
Given the equation:

Follow these steps to solve it:
- Subtract the fractions on the left side of the equation:

- Using the Difference of squares formula (
) we can simplify the denominator of the right side of the equation:

- Multiply both sides of the equation by
and simplify:

- Multiply both sides by
:

- Apply Distributive property and simplify:

- Divide both sides of the equation by -6:

- Factor the equation and solve for "m":

In order to verify it, you must substitute
into the equation and solve it:

<em>NO SOLUTION</em>
Answer:
r = 13
Step-by-step explanation:
r-6=7
Add 6 to each side
r-6+6=7+6
r = 13