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Galina-37 [17]
2 years ago
7

The distance from C to D is 24 miles. The distance from B to C is 2/3 of the distance from C to D. The distance from A to B is 3

/8 of the distance from B to C. What is the distance from A to B?
Mathematics
1 answer:
Naddika [18.5K]2 years ago
5 0

Answer:

AB is 6 miles

Step-by-step explanation:

Here, we want to get AB

From the question;

CD = 24

BC = 2/3 * 24 = 16

AB = 3/8 * BC

AB = 3/8 * 16

AB = 6 miles

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11.(02.03)
Marianna [84]

Answer:

step number 1 is incorrect.

Step-by-step explanation:

Here is the solution of this equation [2x-31-1=2].

2x-31-1=2

or 2x-31=2+1

or 2x=2+1+31

or 2x= 34

or x=34/2

or x= 17

the answer of this equation is X=17.

8 0
3 years ago
5x + (1x+6)= 78<br> BARDZO POTRZEBUJĘ
kifflom [539]

Answer:   x = 12

Step-by-step explanation:  

1. add 5x + 1x which will equal 6x so now your equation is:  6x + 6 = 78

2. subtract 6 from 78 to get 72:  6x = 72

3. divide 72 by 6x to get your answer 12

5 0
3 years ago
Read 2 more answers
ANSWER QUICK AND WILL GIVE 1000 POITS PLEASE!!!!!!!A truck drove 229.77 miles on 11.1 gallons of gas. How far could the truck dr
Archy [21]

Answer:

  • 347.76 miles

Step-by-step explanation:

A truck drove 229.77 miles on 11.1 gallons of gas.

<u>Find the mileage per gallon:</u>

  • 229.77 / 11.1 = 20.7 mpg

<u>Find the distance can be driven on full tank:</u>

  • 20.7 * 16.8 = 347.76 miles
4 0
2 years ago
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Can anyone help me plzzzzz
boyakko [2]

Step-by-step explanation:

cmon man its a blank screen

3 0
3 years ago
Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti
almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

d=v.t

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

d=(x+y).t_1

Where t1=2.5 hours. Substituting values:

20=(x+y)*2.5

Rearranging, we find the downstream equation:

2.5x+2.5y=20\qquad[1]

The speed when rowing upstream is x-y, and the distance traveled is

d=(x-y).t_2

Where t2=5 hours. Substituting values:

20=(x-y)*5

Rearranging, we find the upstream equation:

5x-5y=20\qquad[2]

Multiplying [1] by 2:

5x+5y=40

Adding this equation to [2]:

10x=60

Solving:

x=60/10=6

Dividing [2] by 5:

x-y=4

Solving for y

y=x-4=6-4=2

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0
3 years ago
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