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Trava [24]
3 years ago
10

Which of the following has no solution?

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

(x + 1 s 1) n (x + 12 1)

(x +1<1) n (x + 1 > 1)

Step-by-step explanation:

Just simplify each the statements.

Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.

(x + 1<-1) n (x + 1< 1)

(x <-2) n (x < 0) which is true, so there is a solution.

(x + 1 s 1) n (x + 12 1)

this doesn't make sense so there is no solution.

(x +1<1) n (x + 1 > 1)

(x < 0) n (x > 0)

This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.

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Seven more than a number would be B. d + 7

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Hope this helps :)
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3 years ago
16% of all Americans live in poverty. If 41 Americans are randomly selected, find the probability that
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Energy bars are on sale at 20 bars for $5. How many can<br> you buy for $18?
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Answser:

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Step-by-step explanation:

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3 0
3 years ago
2. Which of the following statements is FALSE?
castortr0y [4]

Answer:

Step-by-step explanation:

Option C

Is the correct answer

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3 0
3 years ago
Read 2 more answers
The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
Deffense [45]

Answer:

a

    f'(t) is  negative

b

 The  unit is degC/min

c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

5 0
3 years ago
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