Answer:
Therefore, 512/128 simplified to lowest terms is 4/1.
Step-by-step explanation:
Reduce 512/128 to lowest terms
The simplest form of
512
128
is
4
1
.
Steps to simplifying fractions
Find the GCD (or HCF) of numerator and denominator
GCD of 512 and 128 is 128
Divide both the numerator and denominator by the GCD
512 ÷ 128
128 ÷ 128
Reduced fraction:
4
1
Therefore, 512/128 simplified to lowest terms is 4/1.
Answer:
a.
Step-by-step explanation:
Answer:
The answer to the question: "Will Hank have the pool drained in time?" is:
- <u>Yes, Hank will have the pool drained in time</u>.
Step-by-step explanation:
To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:
- Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
- Available time = 360 minutes
Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:
- Volume of the pool = Deep * Long * Wide
- Volume of the pool = 2 m * 10 m * 8 m
- Volume of the pool = 160 m^3
Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:
Now, we use a rule of three:
If:
- 1 m^3 ⇒ 264.172 gal
- 160 m^3 ⇒ x
And we calculate:
(We cancel the unit "m^3)- x = 42267.52 gal
At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:
- Time to drain the pool =
(We cancel the unit "gallon") - Time to drain the pool = 325.1347692 minutes
- <u>Time to drain the pool ≅ 326 minutes</u> (I approximate to the next number because I want to assure the pool is drained in that time)
As we know, <u><em>Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes</em></u>.
Answer: 28.26
Step-by-step explanation:
What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²
You are given the diameter in these problems, so you need radius.
For the first circle (8 in one) :
8/2=4 r=4
A=3.14(4)²
A=50.24
For the second one (10 in one) :
10/2=5 r=5
A=3.14(5)²
A=78.5
To find the measure of the annulus, you subtract those numbers, getting 28.26