Answer:
(x + 1 s 1) n (x + 12 1)
(x +1<1) n (x + 1 > 1)
Step-by-step explanation:
Just simplify each the statements.
Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.
(x + 1<-1) n (x + 1< 1)
(x <-2) n (x < 0) which is true, so there is a solution.
(x + 1 s 1) n (x + 12 1)
this doesn't make sense so there is no solution.
(x +1<1) n (x + 1 > 1)
(x < 0) n (x > 0)
This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.
