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Trava [24]
2 years ago
10

Which of the following has no solution?

Mathematics
1 answer:
Softa [21]2 years ago
5 0

Answer:

(x + 1 s 1) n (x + 12 1)

(x +1<1) n (x + 1 > 1)

Step-by-step explanation:

Just simplify each the statements.

Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.

(x + 1<-1) n (x + 1< 1)

(x <-2) n (x < 0) which is true, so there is a solution.

(x + 1 s 1) n (x + 12 1)

this doesn't make sense so there is no solution.

(x +1<1) n (x + 1 > 1)

(x < 0) n (x > 0)

This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.

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What is the domain and range of this graph
kupik [55]

Answer:

The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. (In grammar school, you probably called the domain the replacement set and the range the solution set. further the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

I hope it will help =)

5 0
3 years ago
Find the surface area of the pyramid
jolli1 [7]

The surface area is ≈ 451.92

5 0
3 years ago
Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx  = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

          = 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

           = 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

           = 1/[√3/2cosx + 1/2sinx]

            = 1/(√3cosx + sinx]/2

            = 2/√3cosx + sinx

    R.H.S = L.H.S

Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

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5 0
1 year ago
Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Andrei [34K]

Answer:

Circle 1=6x+2y

Rectangle 4 = 3x+y

Circle 4 = 5x

Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

Combining\:like\:terms\\

4x+2x+3y-y=C1

6x+2y=C1

So, The result is: C1=6x+2y

Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

R1=4x+5y-x-4y

R1=4x-x+5y-4y

R1=3x+y

So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

Now, We need to solve the equation:

Let C4= Circle 4

2x-y+3x+y=C4

Combining the like terms

2x+3x-y+y=C4

5x=C4

So, Solving 2x-y+3x+y=C4 we get C4 = 5x

7 0
3 years ago
Simplify:9-1÷2÷27^2÷3​
sammy [17]

<u>First let's calculate the exponents.</u>

27^2 : 729 = 9-1\div \:2\div \:729\div \:3

<u>Now we should multiply and divide.</u>

<u />1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}<u />

<u>Now we should add and subtract.</u>

<u />9-\frac{1}{4374} :\frac{39365}{4374} =  \frac{39365}{4374}<u />

<u>Convert the improper fractions into mixed numbers.</u>

<u />8\frac{4373}{4374}<u />

<u />

<u>Answer : </u>

<u />8\frac{4373}{4374}<u />

<u />

5 0
2 years ago
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