2 1/4 + 1 1/2
2 + 1 = 3
1/4 + 1/2 = 1/4 + 2/4 = 3/4
so ur answer is 3 3/4 lbs of cheese in total
Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
0.430625=0.431
Step-by-step explanation:
Answer:
0.430625 = 0.431
Step-by-step explanation:
Let W represent winning, D represent a draw and L represent a loss.
12+ points can be garnered in each of the following ways.
6W 0D 0L
5W 1D 0L
5W 0D 1L
4W 2D 0L
4W 1D 1L
4W 0D 2L
3W 3D 0L
The probability of getting 12+ points is the sum of all these 7 probabilities.
Knowing that P(W) = 0.5
P(D) = 0.1
P(L) = 0.4
P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625
P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875
P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075
P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375
P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075
P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15
P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025
The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625
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Answer:
D.x = 6; m∠XOY = 18°
Step-by-step explanation:
Supplementary angles add to 180 and complementary angles add to 90
∠WOZ + ∠WOX = 180
108 + ∠WOX = 180
∠WOX + ∠XOY = 90
∠WOX + 3x = 90
∠WOX = 90 -3x
Replace WOX in the first equation
108 + ∠WOX = 180
108 + 90 -3x = 180
Combine like terms
198 -3x = 180
Subtract 198 from each side
-3x = 180-198
-3x = -18
Divide by -3
-3x/-3 = -18/-3
x = 6
∠XOY = 3x = 3*6 = 18
Answer:
11 rides
Step-by-step explanation:
let the total amount be y
and let the number of ride be x
the expression for the situation is y=mx+c
given
total amount=$28
admission fee= $6
cost per ride=$2
we are expected to find x
substitute into the expression we have
28=2x+6
28-6=2x
22=2x
divide boths sides by 2 we have
x=22/2
x=11
the number of rides is 11
