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3 years ago

12

Jose and Alexia were lab partners in science class. They needed to weigh three samples of rock to the nearest thousandth. The fi

rst sample weighed 3.346 grams, the second weighed 2.479 grams, and the third weighed 9.240 grams. How much did the samples weigh altogether?

2 answers:

Anon25 [30]3 years ago

5 0

15.064 grams.I hope this helps

nadezda [96]3 years ago

4 0

Your answer is 15.065
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2 years ago

At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500

kaheart [24]

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D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

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The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

$P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}$

i.e. $PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}$

Substituting the values, we get,

i.e. $PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}$

i.e. $22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-0.4735]}{0.00625}$

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i.e. $P=\frac{22000\times 0.00625}{0.5265}$

i.e. $P=\frac{137.5}{0.5265}$

i.e. $P=261.16$

Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

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3 years ago

Read 2 more answers

A BMW that cost $71,000 in 2003 depreciates in value about 15% a year. How much was it worth in 2013?

N76 [4]

100-15= 85%

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Did this make sense or would you like me to explain some more about something you are still not understanding? Please comment below :)

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3 years ago