Pls help, u dont have to explain that much

PLEASE HELP FAST WILL MARK BRAINLIEST!!!!!!

puteri [66]

Answer: the second one

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can pretty please help me with 2 math question its due today

Mashcka [7]

Answer:
(4x + 12 ) - ( -8 ) =
4x + 20
Explanation:
Just add them up and form a equation ( this is for the second one )

5 0

3 years ago

Read 2 more answers

A state park charges an entrance fee based on the number of people in a vehicle. A car containing 2 people is charged $14, a car

Artyom0805 [142]

Answer:

Therefore $98 is be charged a bus containing 30 people.

Step-by-step explanation:

Given that,

A state park charges an entrance fee based on the number of people in vehicle.

Let the entry fee for the vehicle be E and entry fee for each person be x.

Then

C= E+(P×x)

C= Total charge in $

E= entry fee for a vehicle

P=No. of person

x= Entry charge per person.

Given A car containing 2 people charged $14

C=$14, P=2

∴14= E+(2× x)

⇒E+2x=14.....(1)

Again A car containing 4 people charged $20

C=$20, P=4

∴20= E+(4× x)

⇒E+4x=20.....(2)

Subtract (1) from (2), we get

E+4x-(E+2x)= 20-14

⇒E+4x-E-2x=6

⇒2x=6

⇒x=3

Putting the value of x in equation (1)

E+(2×3)=14

⇒E=14-6

⇒E=8

Therefore E=$8 and x=$3

Next we check whether our assumption is correct or wrong. Putting the value of E and x for third case

Here P= 8

Therefore C= E+(P×x)

= 8+(8× 3)

=8+24

=$32

Therefore our assumption is correct.

Now C=? , P= 30

The charged for the 30 people is

C= $[8+(30×3)]

=$[8+90]

=$98

Therefore $98 is be charged a bus containing 30 people.

4 0

4 years ago

Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$

The speed at which distance is increasing between the two boats is given as:

$\dfrac{47.17}{2.5} \approx 18.87\ km/hr$

4 0

3 years ago

Identify all factors of the expression 12x^2-14x-6

Evgen [1.6K]

Let's solve this by using the quadratic formula:

$\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Note that we only use the coefficients so a=12, b=-14, and c=-6.

Plug values in the quadratic equation:

$\frac{ - ( - 14)± \sqrt{ {( - 14)}^{2} - 4(12)( - 6) } }{2(12)}$

And so by evaluating those values we obtain:

$\frac{14+-\sqrt{484} }{24}=\frac{14+-22}{24} \\\\$

Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

$\frac{14+22}{24}=\frac{36}{24}=\frac{3}{2}$

Second Factor:

$\frac{14-22}{24}=\frac{-8}{24}=-\frac{1}{3}$

And so your factors are

$\frac{3}{2},-\frac{1}{3}$

meaning that those are your roots/x-intercepts.

6 0

3 years ago

Pls help, u dont have to explain that much ​

Pls help, u dont have to explain that much