For the answer to this questions,<span>a. P (z ≤ z0) = 0.0401=P(z ≥ z0) = 1-0.0401 = 0.9599 = P(z ≤ -z0) = 0.9599
From tables z0 = -1.75
b. P (-z0 ≤ z ≤ z0) = .95 = P (z ≤ z0)- P (z ≤ -z0) = P (z ≤ z0)- P (z ≥ z0) =
P (z ≤ z0)-(1- P (z ≤ z0))
P (z ≤ z0) = (0.95+1)/2=0.975
From tables z0 = 1.96
c. P (-z0 ≤ z ≤ z0) = 0.90
the procedure is the same that exercise b P (z ≤ z0) = (0.9+1)/2=0.95
From tables the nearest value is z0 = 1.64
</span>d. P (-z0 ≤ z ≤ 0) = 0.2967= P (z ≤ 0) - P (z ≤ -z0) = P (z ≤ 0) - P (z ≥ z0) =
<span>P (z ≤ 0) - (1- P (z ≤ z0)) </span>
<span>P (z ≤ z0) = 0.2967 + 1 - P (z ≤ 0)= 0.2967 + 1 - 0.5 = 0.7967 </span>
<span>From tables z0 = 0.83
</span><span>
I hope my answer helped you
</span>
Answer: 6(x-2)
Step-by-step explanation:
(x·2-8)-(2x·2+4)
(2(x-4))+2x·2-4
2(x-4)+2x·2-4
2(x-4)+4x-4
2(x-4+2x-2)
2(3x-4-2)
2(3x-6)
2·3(x-2)
6(x-2)
you find the LCM of 3, 4 and 7 which is 84.
84/3= 28 so x= 28
84/4= 21 so y=21
84/7= 12 so z=12
therefore, 28+21+12= 61. Your answer is D