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dimulka [17.4K]
4 years ago
14

Find a value of the standard normal random variable Z, Call it Z0, such that

Mathematics
1 answer:
katrin [286]4 years ago
5 0
For the answer to this questions,<span>a. P (z ≤ z0) = 0.0401=P(z ≥ z0) = 1-0.0401 = 0.9599 = P(z ≤ -z0) = 0.9599 
From tables z0 = -1.75 

b. P (-z0 ≤ z ≤ z0) = .95 = P (z ≤ z0)- P (z ≤ -z0) = P (z ≤ z0)- P (z ≥ z0) = 
P (z ≤ z0)-(1- P (z ≤ z0)) 
P (z ≤ z0) = (0.95+1)/2=0.975 
From tables z0 = 1.96 

c. P (-z0 ≤ z ≤ z0) = 0.90 
the procedure is the same that exercise b P (z ≤ z0) = (0.9+1)/2=0.95 
From tables the nearest value is z0 = 1.64 

</span>d. P (-z0 ≤ z ≤ 0) = 0.2967= P (z ≤ 0) - P (z ≤ -z0) = P (z ≤ 0) - P (z ≥ z0) = 
<span>P (z ≤ 0) - (1- P (z ≤ z0)) </span>
<span>P (z ≤ z0) = 0.2967 + 1 - P (z ≤ 0)= 0.2967 + 1 - 0.5 = 0.7967 </span>
<span>From tables z0 = 0.83 
</span><span>
I hope my answer helped you

</span>
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If f(x)=x^2 is horizontally compressed to g(x), which could be the equation of g(x)?
leva [86]

For the definition of <em>horizontal</em> compression, the function f(x) = x² is horizontally compressed to the function g(x) = (k · x)², for 0 < k < 1.  

<h3>How to find the resulting equation after applying a compression</h3>

Here we must narrow a given function by a <em>rigid</em> operation known as compression. <em>Rigid</em> transformations are transformations in which <em>Euclidean</em> distances are conserved. In the case of functions, we define the horizontal compression in the following manner:

g(x) = f(k · x), for 0 < k < 1     (1)

If we know that f(x) = x², then the equation of g(x) is:

g(x) = (k · x)², 0 < k < 1

For the definition of <em>horizontal</em> compression, the function f(x) = x² is horizontally compressed to the function g(x) = (k · x)², for 0 < k < 1.      

To learn more on rigid transformations: brainly.com/question/1761538

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5 0
2 years ago
Question Content Area
kap26 [50]

b. Total fixed cost are $49885

<h3>What is fixed cost of product ?</h3>

Sometimes production of a product may increase or decrease, but the cost which do not change with the change of output is called fixed cost of the product.

<h3>What is the total fixed cost ?</h3>

Highest monthly total cost = $83800

Highest monthly production units = 3500 desks

Lowest monthly total cost = $61900

Lowset monthly production units = 1240 desks

So, variable cost per unit = (Highest cost-lower cost)/(highest production units-lowest production units)

= ($83800-$61900)/(3500-1240)

= $21900/2260

= $9.7

∴ Total fixed costs=Highest monthly total cost-(highest production units×variable cost per unit)

= $83800-(3500×$9.7)

= $83800-$33950

= $49850

Nearest value is $49885, whch is the correct one.

Learn more about fixed cost here:

brainly.com/question/27328807

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3 0
2 years ago
A cannon is placed on high ground 24 ft above a target that is 1000 ft away horizontally. It fires a projectile upward at a 45°
topjm [15]

Answer:

D. vo = 125(2)^1/2

Step-by-step explanation:

Range of a projectile is the defined as the distance covered in the horizontal direction.

Range = U²sin2θ/g

U is the speed of the object

θ is the angle of launch

g is the acceleration due to gravity

If the target is 1000 ft away horizontally, range = 1000ft

θ = 45°

g = 32ft/s²

1000 = U²sin2(45°)/32

32000 =U²sin90°

32000 = U²

U = √32000

U = 125√2 m/s

4 0
3 years ago
Solve the question for the letter r: d=rt
topjm [15]
So we are just solving for R?

     d = rt
   d/t = rt/t
   d/t = r

Simply isolate the r to one side, using the principle "what you do to one side, you must do to the other." 
 
ANSWER: r = d/t 
                       ( d divided by t)

Hope this helps!! God bless! :)
3 0
3 years ago
If logM/N=5 and logP/N=7, what can you say about the relationship between M and P?. . A. M=2P. B. P=2M. C. P=100M. D. P=10M
liubo4ka [24]
<span>log (M/N) = log M - log N
 so log M - log N = 5
log (P/N) = log P - log N
so log P - log N = 7
 If you subtract equation 2 from equation 1, you have log M - log P = -2
 That means that log (M/P) = -2 ----> 10^-2 = M/P ---> P = 100M</span>
8 0
3 years ago
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