Answer:
20 goes into 110 five-and-a-half times
Step-by-step explanation:
Let's show our work:
20 + 20 + 20 + 20 + 20 + 10
\____\_____\____/_____/_____/
100
100
= 20 + 20 + 20 + 20 + 20 + 10
Half of 20 = 10
The keyword is half - so that leaves a 0.5 in your answer to "How many times does 20 go into 110."
How many 20's are there? Let's count!
20 + 20 + 20 + 20 + 20
1 2 3 4 5
So five 20's + one 0.5 = ?
That equals 5.5, because 5 + 0.5 = 5.5
Your answer is 5.5!
I hope this helps!
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
Answer:
So the answer is 108.75
Step-by-step explanation:
15 * $4.25 = 63.75
12* $3.75 = 45
63.75 + 45 = 108.75.
Answer:108.75
Step 1
<u>Find the value of s</u>
we know that
In a Rhombus all sides are congruent
so
equate AB and CD
Combine like term
<u>The answer Part a) is</u>
the value of s is 
Step 2
<u>Find the value of side AB</u>
substitute the value of s
Remember that the sides are congruent
therefore
<u>the answer Part b) is</u>
The length of the side BC is 
