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Zolol [24]
3 years ago
8

A line passes through the point (2,3) and has a slope of 0, what equation of the line?

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer: B

Step-by-step explanation: put the points on a graph

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What is the equation of the line? <br><br> Use y = mx+b
Olegator [25]

Answer:

y = - \frac{1}{2} x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (4, 2) ← 2 points on the line

m = \frac{2-3}{4-2} = - \frac{1}{2}

Note the line crosses the y- axis at (0, 4) ⇒ c = 4

y = - \frac{1}{2} x + 4 ← equation of line

8 0
3 years ago
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A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
2 years ago
The point (-2, 4) is plotted on the coordinate plane.
Masteriza [31]

Answer:

I would say B

Step-by-step explanation:

6 0
3 years ago
What is the value of x?
Vlad1618 [11]

Answer:

A

Step-by-step explanation:

using pythagoras theorem

h²=p²+b²

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2 years ago
I WILL GIVE BRAINLIEST IF YOU ANSWER THIS QUESTION (correct or not)
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Answer:

$27.25

Step-by-step explanation:

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