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Romashka-Z-Leto [24]
3 years ago
8

PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!
PLSSSS SHOWWW THE WORKKK!!!!

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer:

16a^7 b ^14

Step-by-step explanation:

joja [24]3 years ago
6 0

Answer:

8a^6b^10

Step-by-step explanation:

First you want to multiply 2ab^4 by 2

2a^4b^2(2ab^4)^2

Then you want to multiply the numbers together 2x2x2 and add the exponents that goes with the same variable a=4+1+1 b=2+4+4

2a^4b^2 2ab^4 2ab^4

Finally, you have your answer.

8a^6b^10

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Please help with question 15 and 16!!!
kykrilka [37]
15. [4] insufficient information. only given SA
16. There are 3 right triangles, 3 Pythagorean theorem equations 
x²+b²= 16²
12²+a² = x²
a²+4² = b²

combine equations using substitution to get in terms of only x
substitute b² for (a² +x²) in first equation
x²+a²+4²=16²
substitute a² for (x² - 12²)
x²+x²-12²+4² = 16²
solve for x
2x² - 144 + 16 = 256
2x² = 256 + 144 - 16
2x² = 384
x² = 384/2
x² = 192
x = 13.85

rounded to nearest tenth, x = 13.9




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