What is the main difference between a search engine and a web browser?

QUESTIONS Which of the following use cases are suitable for compute-optimized cloud offering? ОА. None of the listed O B. Highly

Ede4ka [16]

Answer:

E. All of the listed

Explanation:

For compute-optimized cloud offerings like AWS, suitable use cases are - gaming, distributed analytics, and scientific modeling. Since all these are suitable, the correct answer is E.

4 0

3 years ago

The technique helps you explore possible risks by providing access to risk areas identified in the past. It also provides the so

Elza [17]

Answer:

The technique helps you explore possible risks by providing access to risk areas identified in the past is explained below in details.

Explanation:

Risk administration commences with the system of classifying risks. In this method, we examine future developments or circumstances that may influence our understanding and capacity to accomplish our aims. Risk identification incorporates estimating out where, when, how, and why such situations may happen.

7 0

3 years ago

Another html/css assignment, drop css code below, thank you

Reil [10]

This is what I come up with. I'm unclear what the 4th requirement means, so I've labeled it #unclear.

a { color : red; }

p:not(:first-child) { text-indent: 5%; }

div { background-color: aqua; }

#unclear { width: 50%; margin-left: 25%; margin-right: 25%; }

.links:link { font-size 24px; background-color: yellow; }

#first { text-transform: uppercase; font-style: italic; }

6 0

4 years ago

project-1 Write a class called Person that has two data members - the person's name and age. It should have an init method that

MArishka [77]

Hello how are you today

4 0

3 years ago

g % Create a program to plot the motion of the ping pong ball with drag. % The program will take inputs for velocity in m/s and

Gala2k [10]

Answer:

% Create a program to plot the motion of the ping pong ball with drag.

% The program will take inputs for velocity in m/s and angle of launch.

% note that with a high speed camera I estmated a launch speed for a ping

% pong ball could be 30 m/s.

clear all

close all

clc

velStart=input('input the initial velocity in m/sec: ');

angle=20:5:80;

% convert the degrees into radians so MATLAB likes it

values_angle=angle*pi./180;

rangeAngle=length(values_angle);

hold on

%Lines 1 - 14 are fine

for i=1:rangeAngle

% set initial position and time

x=[];

y=[];

time=[];

vel=velStart;

VelocityX=[];

VelocityY=[];

x(1)=0; % meters

y(1)=.001; % meters

time(1)=0; % seconds

mass=.00247; %kg ping pong ball .00247 Kg

g=-9.8; % m/sec^2

c=0.0005; % coefficient of drag where Re is between 10^3 and 10^5

% so I can load an array for plotting

% start to increment the motion

index=1;

thisAngle=values_angle(i);

velx=vel*cos(thisAngle);

VelocityX(1)=velx;

vely=vel*sin(thisAngle);

VelocityY(1)=vely;

% set a time step

deltaTime=.001; % seconds

height=y(1);

flag=0;

velFinalX = 0;

velFinalY = 0;

%Don't see any issues here

while height>0 % check that the ball has not hit ground yet (1e-3 to speed things up, It hangs because it never leaves this line, check how height is calculated.)

index = index+1;

% *******************************************************

% break velocity into its components

if index == 2

velx = vel*cos(thisAngle);

vely = vel*sin(thisAngle);

else

velx = velFinalX;

vely = velFinalY;

end

% *******************************************************

% use an if/else statement to check to see if the ball is moving

% down (negative). If it is, then drag has an opposite sign

% as gravity in the acceleration formula. Otherwise gravity

% and drag have the same sign. Calculate the new acceleration in the y.

if vely < 0

adragy = g + (c*vely.^2)/mass;

velFinalY = vely + adragy.*deltaTime;

else

adragy = g - (c*vely.^2)/mass;

velFinalY = vely + adragy.*deltaTime;

end

% *******************************************************

% Now calculate the acceleration in the x .

adragx = (-c*velx.^2)/mass;

% *******************************************************

% *****************************************************

% calculate the new velocity at the end of the time step

% this will have X and Y components, so you need a variable

% for each. One is velFinalX and the other is velFinalY.

velFinalX = velx + adragx.*deltaTime;

% velFinalY = vely + adragy.*deltaTime;

% *******************************************************

% ******************************************************

% Get a new velocity vector and angle given the X and Y

% The velocity is the variable "vel" and angle is "angle"

vel = sqrt(velFinalX.^2 + velFinalY.^2);

angle = atan(velFinalY/velFinalX);

%*******************************************************

% now save my values at this time step

VelocityX(index)=velFinalX;

VelocityY(index)=velFinalY;

% and distance numbers

distX=VelocityX(index).*deltaTime;

distY=VelocityY(index).*deltaTime;

% save distance values

x(index)=x(index-1)+distX;

y(index)=y(index-1)+distY;

height=y(index);

time(index)=time(index-1)+deltaTime;

%lines 105-107 are good

if distY<0&&flag<=1

if height<.25

disp(distY)

fprintf('goal height detected at distance %.2f meters.',x(index));

flag =2;

LandingDistance(i)=x(index);

end

plot(x,y)

title('distance traveled by ping pong ball in meters')

xlabel('horizontal distance traveled (meters)')

ylabel('vertical distance traveled (meters)')

end

hold off

Explanation:

7 0

4 years ago