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sweet-ann [11.9K]
4 years ago
8

What is 2/3-5/9 in 5th grade math

Mathematics
2 answers:
Helga [31]4 years ago
6 0

Answer:

Step-by-step explanation:

Solution

=2×3/3×3-5×1/9×1

=6/9-5/9

=6-5/9

=1/9

Please mark me brainliest.Ok

solmaris [256]4 years ago
4 0

Answer:

0.111111

Step-by-step explanation:

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the cost of having one shirt laundered is 6 dollars. each additional shirt costs 4 dollars. write the explicit and recursive for
Katarina [22]

Answer:

<h3>explicit formula- a(n)=6+4(n-1)</h3><h3>recursive formula- a(n)=a(n)-1 +4; a(1)=6</h3>

Step-by-step explanation:

4 0
3 years ago
For each polynomial function,
Allisa [31]
<span>f(x)=x^3-4x^2+2x+4, we know that f(2)=8-16+4+4=16-16=0
and we can write f(x)= (x-2)Q(x) so Q(x) = f(x) / (x-2)=x²-2x-2
</span><span>x²-2x-2=0   delta = (-1)²- (1).(-2) =1+2=3
</span>x=1-sqrt3  or <span>x=1+sqrt3  
finally the zeros are x=2, </span>x=1-sqrt3  or <span>x=1+sqrt3 </span>
6 0
4 years ago
HURRRRYYY <br>Hurry pleaseee use elimination show your work <br><br><br>15y - 9x =-9 -8y+9x=12
Nastasia [14]
Add the two functions together to get

7y=-3
y=-3/7

Then plug in y to either function to solve for x, I’ll just use the left one

15(-3/7)-9x=-9
-45/7-9x=-9
-9x=-18/7
x=18/7/9

x=2/7
6 0
2 years ago
Our class has 50 students. Assuming that no students are born on leap days (February29), what is the probability that no two stu
madreJ [45]

Answer:  a) \dfrac{799}{31250}  b) \dfrac{30451}{31250}

Step-by-step explanation:

Since we have given that

Number of days in a year = 365

Number of students = 50

Probability that no two students share the same birthday. It means each student has different birthday.  

Probability(no two students share the same birthday)=\dfrac{365-1}{365}\times \dfrac{365-2}{365}........\times \dfrac{365-50}{365}

Probability(no two students share the same birthday)=\dfrac{^{365}P_{50}}{365^{50}}

Probability(no two students share the same birthday)=\dfrac{799}{31250}\approx 0.025568

Probability that at least one of the students has the same birthday as another student in the class is given by

1-P(\text{no student share the same birthday})\\\\=1-\dfrac{799}{31250}\\\\=\dfrac{30451}{31250}=0.974432

5 0
4 years ago
Approximate to the nearest tenth the real zeros of f(x)=-5<img src="https://tex.z-dn.net/?f=x%5E%7B3%7D" id="TexFormula1" title=
Vera_Pavlovna [14]
To the nearest tenth the zeroes are:
x=-0.2, x=-0.7 \:and\: x=2.7

EXPLANATION

f(x)=-5x^3+9x^2+12x+2

The constant term is 2, and the coefficient of the highest degree is -5 so test all rational factors of

-\frac{2}{5}

These are;

\frac{1}{5},\frac{2}{5},-\frac{1}{5}, -\frac{2}{5}

f(-\frac{1}{5})=-5(-\frac{1}{5})^3++9( -\frac{1}{5})^2+12( -\frac{1}{5})+2

f(-\frac{1}{5})=\frac{5}{125}+\frac{9}{25}-(\frac{12}{5})+2

f(-\frac{1}{5})=\frac{5+45-300+250}{125}=\frac{0}{125}=0

Good for us the very first one is a root. Therefore,

x=-\frac{1}{5}

is a root. These also means that

(5x+1)

is a factor. Therefore we perform long division to find the other factors as follows.

We can now factor the polynomial as,

f(x)=-(5x+1)(x^2-2x-2)

f(x)=-(5x+1)(x^2-2x-2)=0

This implies that,

-(5x+1)=0

Which gives us

x=-\frac{1}{5}=-0.2

Or

x^2-2x-2=0

\Rightarrow x^2-2x=2

We complete the square to obtain,

(x-1)^2=2+1

\Rightarrow (x-1)^2=3

Taking square root of both sides gives;

\Rightarrow x-1=\pm \sqrt{3}

This implies

x=1-\sqrt{3}=-0.7

x=1+\sqrt{3}=2.7
7 0
4 years ago
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