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yan [13]
3 years ago
15

Question 42 points) Tell whether the triangles are similar. Yes or No

Mathematics
2 answers:
Bad White [126]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

Natali [406]3 years ago
3 0

Answer:

yes. 81+51+48 = 180

I hope this helps

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Ana’s location is -30 feet below the cave entrance, Chilean location is -12 below the cave entrance. Which girl is located farth
sattari [20]

Answer:

Ana

Step-by-step explanation:

4 0
3 years ago
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Angles C and E are complementary angles. Angle C measures (4× + 50). Angle E measures 28 degrees. Solve for x.​
julsineya [31]

Answer:

x = 3

Step-by-step explanation:

4x + 50 + 28 = 90

4x + 78 = 90

4x = 12

x = 3

7 0
3 years ago
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Can someone answers this question please master it correctly if it’s corect I will mark you brainliest
GarryVolchara [31]

Answer:

4 bowlers

Step-by-step explanation:

There are 18 different hats, 6 are bowlers

Find the unit rate: 6/18 or 1/3

1 bowler out of 3 hats

4 bowlers out of 12 hats

<h3><u><em>Hope this helps!!!</em></u></h3>

4 0
3 years ago
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Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

We are given the following integral:

\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

8 0
3 years ago
1. In which quadrant does θ lie given that sinθ&gt;0 and cosθ&lt;0?
expeople1 [14]

Answer:

\theta is in quadrant II

Step-by-step explanation:

Given

\sin(\theta)  > 0 and \cos(\theta)  < 0

Required

Where is \theta

\sin(\theta)  > 0 and \cos(\theta)  < 0 imply that

\theta is in quadrant II

Because that is only quadrant where \sin(\theta)  > 0 and \cos(\theta)  < 0 exist.

4 0
3 years ago
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