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kirza4 [7]
3 years ago
14

1. In which quadrant does θ lie given that sinθ>0 and cosθ<0?

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

\theta is in quadrant II

Step-by-step explanation:

Given

\sin(\theta)  > 0 and \cos(\theta)  < 0

Required

Where is \theta

\sin(\theta)  > 0 and \cos(\theta)  < 0 imply that

\theta is in quadrant II

Because that is only quadrant where \sin(\theta)  > 0 and \cos(\theta)  < 0 exist.

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A rocket is launched into the air. The height h(t), in yards, of the rocket is a function of time, t, in seconds, as shown in th
Vesna [10]

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope.  Because this is parabolic, we cannot find the exact rate of change as we could if this were a linear function.  But we can use the same idea.  When t = 3, h(t) = 33, so the coordinate point is (3, 33).  When t = 6, h(t) = 0, so the coordinate is (6, 0).  Plug those values into the slope formula:

m=\frac{0-33}{6-3} and

m=\frac{-33}{3} which is -11

From 3 to 6 seconds, the rocket is falling 11 yards per second.

8 0
3 years ago
PLEASE HELP ME IM GIVEING POINTS AWAY BEING TOO LAZY TOO SOLVE MY CLASS WORK LOL
katen-ka-za [31]

Answer:

17/24

Step-by-step explanation:

Apply the AB rule, Adjust the fractions based on LCM, then you want to apply the a/b fraction rule which would allow you to do -15+23/24 which gives you 17/24. Hope this helps!

3 0
3 years ago
Read 2 more answers
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
Adam writes 18y to simplify an expression with three like terms. What could the expression be?
frosja888 [35]

Answer:

Step-by-step explanation:

5y + 6y + 7y = 18y......any numbers that add(or subtract) to equal 18, stick them before the y....

or it could be : 10y + 10y - 2y = 18y or 5y + 10y + 3y or 30y - 20y + 8y....I could go on forever...lol

8 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
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