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Answer:
public class Triangle
{
public static void main( String[] args )
{
show( 5 );
}
public static void show( int n )
{
int i,j,k;
for (i = 0; i < n - 1; i++ )
{
for (j = 0; j < i; j++ )
{
System.out.print( " " );
}
for (k = n - i; k > 0; k-- )
{
System.out.print( "* " );
}
System.out.println();
}
for (i = 0; i < n; i++ )
{
for (j = n - i; j > 1; j-- )
{
System.out.print( " " );
}
for (k = 0; k < i + 1; k++ )
{
System.out.print( "* " );
}
System.out.println();
}
Answer:
Only
Option: void f1(float array[], int size);
is valid.
Explanation:
To pass an array as argument in a function, the syntax should be as follows:
functionName (type arrayName[ ] )
We can't place the size of the array inside the array bracket (arrayName[100]) as this will give a syntax error. The empty bracket [] is required to tell the program that the value that passed as the argument is an array and differentiate it from other type of value.
<span>C. Rulers indicate the margins, tabs, and indents in a presentation slide.
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