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3 years ago

What is the exponent for the expression 6x6x6x6x6x6x6?

Mathematics

2 answers:

Artist 52 [7]3 years ago

6 0

Answer:7 is the exponent

Step-by-step explanation:

netineya [11]3 years ago

6 0

Answer:

$6^7$

Step-by-step explanation:

Exponents can be expressed through repeated multiplication, meaning that the amount of times one number is being repeated, would be the same amount as put in an exponent. Therefore :

6 * 6 * 6 * 6 * 6 * 6 * 6

6 is being repeated, therefore it's the constant.

6 is repeated 7 times, therefore the exponent is 7.

$6^7$

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Https://www.hmhco.com/one/assessment/#/formativeLive Assessment/

GuDViN [60]

A. equation: y = -3x - 2

B. y-intercept: -2

Solution:

Given that,

Write the equation 12x = - 4y - 8 in slope-intercept form

The slope intercept form is given as:

$y = mx + c$

Where,

m is the slope and "c" is the y intercept

From given

$12x = -4y - 8\\\\Rewrite\\\\-4y-8 = 12x\\\\Move\ the\ constant\ to\ right\ side\\\\-4y = 12x + 8\\\\y = \frac{12x}{-4} + \frac{8}{-4}\\\\y = -3x -2$

Thus the slope intercept form is found

Comparing with y = mx + c ,

c = -2

Thus the y intercept is -2

3 0

3 years ago

Consider "Never Retreat" as a whole.

insens350 [35]

Answer: 3+3=9

⇔

Step-by-step explanation: three fingers to start add three fingers total of nine

4 0

2 years ago

What is the square root of 378904

zvonat [6]

Simplify the following:

sqrt(378904)

sqrt(378904) = sqrt(8×47363) = sqrt(2^3×47363):

sqrt(2^3 47363)

sqrt(2^3 47363) = sqrt(2^3) sqrt(47363) = 2 sqrt(2) sqrt(47363):

2 sqrt(2) sqrt(47363)

sqrt(2) sqrt(47363) = sqrt(2×47363):

2 sqrt(2×47363)

2×47363 = 94726:

Answer: 2 sqrt(94726)

6 0

3 years ago

A diver went 25.65 feet below the surface of the ocean and then 16.5 feet further down he then rose 12.45 feet. Write and solve

trasher [3.6K]

X= 25.65 + 16.5 - 12.45
X=29.70

6 0

3 years ago

Read 2 more answers

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago