If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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X is equal to 12 and y is equal to 8
Answer:
39 cups
Step-by-step explanation:
If we assume that the 3.5 cups of concentrate make 3.5+3 = 6.5 cups of tea, we can use the proportion ...
6.5/3.5 = x/21
to find the x cups of tea Ahab can make with 21 cups of concentrate.
Multiplying by 21, we get ...
x = 21(6.5/3.5) = 39
Ahab can make 39 cups of tea.
Answer:
answer D ( if i interpreted your question correctly )
Step-by-step explanation:
Sqrt (c^2) = √(c^2) = C
Answer:
SAS Postulate
Step-by-step explanation:
You can use the SAS (side, angle, side) postulate that says "if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent"
Side AB is proportionate to DE and
Side AC is proportionate to DF.
Angle A and Angle D are the same; and is between the two sides
I hope this helps.
