2 years ago

Given the quadratic function f(x) = 2x²- 6x + 7i Find the vertex of f(x).

Mathematics

1 answer:

Alenkasestr [34]2 years ago

8 0

Answer:

(3/2, 5/2)

Step-by-step explanation:

The x value for the vertex of a parabola in the form y=ax^2+bx+c is -b/2a. The x value is then plugged into the function to find the y value.

You might be interested in

Put these fractions in order from smallest to greatest<br><br> 3/4, 2/7, 2/10, 5/8, 2/3, 8/4

Flura [38]

The answer to the question

8 0

2 years ago

I need help thank you

Alik [6]

2 is the quotient

-26

-24

8

7 0

2 years ago

Find the parabola with equation y = ax2 + bx whose tangent line at (3, 12) has equation y = 10x − 18. y = incorrect: your answer

pishuonlain [190]

For these questions to be true and the equation of the tangent to have an equal y to the equation of the parabola i guess there has to be a "c" and in that case integrate the equation of the tangent you will have a = 5 and b = -18 then you substitute in the equation of the parabola with the point you have you will find that "c" = 21 and so the equation of the parabola becomes y = 5x^2 - 18 x +21

3 0

2 years ago

Which quadratic function in standard form can be represented by the graph that has a vertex at (6, 3) and passes through the poi

xenn [34]

Answer:

Step-by-step explanation:

8 0

2 years ago

Factor and solve the equation

murzikaleks [220]

$y=4x^2-64=4(x^2-16)=4(x^2-4^2)=4(x-4)(x+4)\\\\-------------------------------\\\\4(x-4)(x+4)=0\iff x-4=0\ or\ x+4=0\\\\x=4\ or\ x=-4$

8 0

2 years ago

Given the quadratic function f(x) = 2x²- 6x + 7i Find the vertex of f(x).​

Given the quadratic function f(x) = 2x²- 6x + 7i Find the vertex of f(x).