All categories

3 years ago

What is the value of a in the equation 5a-10b=45 when b=3

2 answers:

7 0

Since b = 3 the equation changes

5a - 10(3) = 45
5a - 30 = 45

(Add 30 to both sides)
5a = 75
Divide 5 to both sides
a = 15

spin [16.1K]3 years ago

6 0

If you would like to solve the equation 5 * a - 10 * b = 45, when b = 3, you can calculate this using the following steps:

b = 3
5 * a - 10 * b = 45
5 * a - 10 * 3 = 45
5 * a - 30 = 45
5 * a = 45 + 30
5 * a = 75 /5
a = 75 / 5
a = 15

Result: The value of a is 15.

You might be interested in

PLEASE HELP ME <br> SHOW ALL THE WorK BC I DONT know how to do it.<br> Will give brainliest

Citrus2011 [14]

Answer:

answer below

Step-by-step explanation:

∠3 = 76°

∠1 = ∠3 = 76° (vertical angle)

∠2 = 180 - ∠1 = 180° - 76° = 104° (supplementary adjacent angle)

∠4 = ∠2 = 104° (vertical angle)

3 0

2 years ago

Jordan is 12 years older than Anna. The

user100 [1]

9514 1404 393

Answer:

J = [12] +A
J + A = [50]

Step-by-step explanation:

If Anna's age is represented by A, then 12 more than Anna's age will be ...

12 + A

Jason's age is said to be 12 more than Anna's age, so ...

J = 12 + A

The sum of their ages will be J + A. That is said to be 50, so ...

J + A = 50

_____

These equations can be solved by using the first to substitute for J in the second.

(12 +A) +A = 50

2A = 38 . . . . . . . . subtract 12

A = 19 . . . . . . . . . . divide by 2

J = 12 +19 = 31 . . . find Jason's age

Jason is 31; Anna is 19.

4 0

2 years ago

Help me please! Literally don’t understand the question.

andrey2020 [161]

I think it's d hope it helps

6 0

3 years ago

Read 2 more answers

X^3-3x^2+x-2=0 how much should x be? And how do you get the answer?

irina [24]

2.89
Graph each side of the equation. The solution is the x-value or the point intersection.

5 0

2 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago