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Diano4ka-milaya [45]
3 years ago
15

What is the value of a in the equation 5a-10b=45 when b=3

Mathematics
2 answers:
valentina_108 [34]3 years ago
7 0
Since b = 3 the equation changes

5a - 10(3) = 45
5a - 30 = 45

(Add 30 to both sides)
5a = 75
Divide 5 to both sides
a = 15
spin [16.1K]3 years ago
6 0
If you would like to solve the equation 5 * a - 10 * b = 45, when b = 3, you can calculate this using the following steps:

b = 3
5 * a - 10 * b = 45
5 * a - 10 * 3 = 45
5 * a - 30 = 45
5 * a = 45 + 30
5 * a = 75       /5
a = 75 / 5
a = 15

Result: The value of a is 15.
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A researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average. She takes a rando
vivado [14]

Answer:

a. No, there is not enough evidence to support the claim using a level of significance of 1%.

b. Null Hypothesis, H_0 : \mu \geq 18.7 months  

c. Alternate Hypothesis<u>,</u> H_A : \mu < 18.7 months

d. P-value of hypothesis test = 0.0199 or 1.99%

e. We conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

Step-by-step explanation:

We are given that a researcher wants to check the claim that convicted burglars spend less than 18.7 months in jail, on average.

She takes a random sample of 67 such cases from court files and finds that the mean is 16.8 months with a standard deviation of 7.3 months.

<em><u>Let </u></em>\mu<em><u> = true mean time convicted burglars spend in jail.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq 18.7 months   {means that the convicted burglars spend more than or equal to 18.7 months in jail, on average}

<u>Alternate Hypothesis,</u> H_A : \mu < 18.7 months   {means that the convicted burglars spend less than 18.7 months in jail, on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean time spent in jail = 16.8 months

             s = sample standard deviation = 7.3 months

             n = sample of cases = 67

So, <em><u>test statistics</u></em>  =   \frac{16.8-18.7}{\frac{7.3}{\sqrt{67} } }  ~ t_6_6

                               =  -2.13

Hence, the value of test statistics is -2.13.

<u>Now, P-value of the test statistics is given by;</u>

      P-value = P( t_6_6 < -2.13) = 0.0199 or 1.99%

  • If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.
  • If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.0199 or 1.99% which is clearly higher than the level of significance of 1%, so we will not reject our null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the convicted burglars spend more than or equal to 18.7 months in jail, on average.

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Answer:

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Step-by-step explanation:

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<em>-3 x + 0.1 + 10 x = x + 4</em>

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<em> x = \frac{3.9}{6}</em>

<em>x = \frac{1.3}{2}</em>

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Answer:

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Step-by-step explanation:

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Hope this helps :)

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